Mathématiques

Question

Bonsoir Pouvez-vous me résoudre ces équation en détaillant bien c'est très important ! Merci :)

1) (4x-2)(7x+1)(12x-6)=0
2) (2x-1)²=(2x-1)(x+3)
3) (2x-1)(x+1)= 5x+5
4) (x²-2x)/(2+x) = 0
5) (x²-9)/(3x)=0
6) ((x/2)-1)/(3-2x)=2
7) (x+1)/(2)+(x+2)/(3)+(x+3)/(4)=12x-1
8)(x+1)²-(2x+2)=0
9)(4x²-9)-2(2x-3)+x(2x-3)=0

Merci de bien détailler !

1 Réponse

  • Bonjour

    1) (4x-2)(7x+1)(12x-6)=0

    4x -2 = 0

    4x = 2

    X = 2/4 = 1/2

    7x + 1 = 0

    7x = -1

    X = -1/7

    12x -6 = 0

    12x = 6

    X = 6/12 = 1/2

    2) (2x-1)²=(2x-1)(x+3)

    (2x-1)^2 -(2x-1)(x+3) = 0

    (2x-1)(2x-1-x-3) = 0

    (2x-1)(x-4) = 0

    2x -1 = 0

    2x = 1

    X = 1/2

    X-4 = 0

    X = 4

    3) (2x-1)(x+1)= 5x+5

    (2x-1)(x+1) -5x -5 = 0

    (3x-1)(x+1) -5(x+1) = 0

    (X+1)(3x-1-5) = 0

    (X+1)(3x-6) = 0

    X + 1 = 0

    X = -1

    3x-6 = 0

    3x = 6

    X = 6/3 = 2


    8)(x+1)²-(2x+2)=0

    (X+1)^2 -2(x+1) = 0

    (X+1)(x+1-2) = 0

    (X+1)(x-1) = 0

    X + 1 = 0

    X = -1

    X-1 = 0

    X = 1

    9)(4x²-9)-2(2x-3)+x(2x-3)=0

    (2x-3)(2x+3) -2(2x-3) + x(2x-3) = 0

    (2x-3)(2x+3-2+x) = 0

    (2x-3)(3x+1) = 0

    2x-3 = 0

    2x = 3

    X = 3/2

    3x +1 = 0

    3x = -1

    X  = -1/3

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