Mathématiques

Question

bonjour,
il faut factoriser en détaillant les étapes merci
C = - (5x + 10) - ( -9x + 10) ( 5x + 10)
E = ( 9x - 10) ( 10x - 10) + 100x² - 100
F= ( -5x + 7)² - ( -5x + 7 ) ( 5x + 4)

2 Réponse

  • Bonjour

    C = - (5x + 10) - ( -9x + 10) ( 5x + 10)

    (5x+10)(-1+9x-10)

    (5x+10)(9x-11)

    5(x+2)(9x-11)

    E = ( 9x - 10) ( 10x - 10) + 100x² - 100

    (9x-10)(10x-10) + (10x+10)(10x-10)

    (10x-10)(9x-10+10x+10)

    (10x-10)(19x)

    19x(10x-10)

    190x(x-1)

    F= ( -5x + 7)² - ( -5x + 7 ) ( 5x + 4)

    (-5x+7)(-5x+7 -5x-4)

    (-5x+7)(-10x+3)

  • Bonjour

    factoriser en détaillant les étapes  

    C = - (5x + 10) - ( -9x + 10) ( 5x + 10)

    C = (5x + 10) * -1 - (-9x + 10)(5x + 10)

    C = (5x + 10)(-1 + 9x - 10)

    C = (5x + 10)(9x - 11)

    C = 5(x + 2)(9x - 11)


    E = ( 9x - 10) ( 10x - 10) + 100x² - 100

    E = (9x - 10) * 10(x - 1) + (10x)² - 10²

    E = 10(9x - 10)(x - 1) + (10x - 10)(10x + 10)

    E = 10(9x - 10)(x - 1) + 10(x - 1) * 10(x + 1)

    E = 10(x - 1)[9x - 10 + 10(x + 1)]

    E = 10(x - 1)(9x - 10 + 10x + 10)

    E = 10(x - 1)(19x)

    E = 190x(x - 1)


    F= ( -5x + 7)² - ( -5x + 7 ) ( 5x + 4)

    F = (-5x + 7)(-5x + 7 - 5x - 4)

    F = (-5x + 7)(-10x + 3)

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