Mathématiques

Question

bonjour (3eme) je n'arrive pas a résoudre les equations suivantes :
a)5(x + 4) = 14 - 3x
b) 4( x - 2) = -2(x + 1) +5
c) 4(x^{2} - 2x - 3) + 1 = (2x - 1)^{2}
d) ( x + 3)(x - 2) = (x - 4)(x - 5) + 3x + 15
Merci d'avance.

2 Réponse

  • Bonjour

    résoudre les equations suivantes :

    a)5(x + 4) = 14 - 3x

    5x + 20 = 14 - 3x

    5x + 20 - 20 = 14 - 3x - 20

    5x + 3x = -6 - 3x + 3x

    8x = -6

    8x/8 = -6/8

    x = -6/8

    x = -3/4


    b) 4( x - 2) = -2(x + 1) +5

    4x - 8 = -2x - 2 + 5

    4x + 2x = 3 + 8

    6x = 11

    x = 11/6


    c) 4(x^{2} - 2x - 3) + 1 = (2x - 1)^{2}

    4x^2 - 8x - 12 + 1 = 4x^2 - 4x + 1

    4x^2 - 4x^2 - 8x + 4x = 1 - 1 + 12

    -4x = 12

    x = -12/4

    x = -3


    d) ( x + 3)(x - 2) = (x - 4)(x - 5) + 3x + 15

    x^2 - 2x + 3x - 6 = x^2 - 5x - 4x + 20 + 3x + 15

    x - 6 = -6x + 35

    x + 6x = 35 + 6

    7x = 41

    x = 41/7

  • bonjour

    a) 5(x+4)=14-3x
    5x+20=14-3x
    5x+3x=14-20
    8x=-6
    x=-6/8
    x=-3/4

    b) 4(x-2)= -2( x+1)+5
    4x-8=-2x-2+5
    4x+2x=3+8
    6x=11
    x=11/6

    c) 4(x^{2}-2x-3)+1=(2x-1)^{2}
    4x^{2}-8x-12+1=(2x-1)(2x-1)
    4x^{2}-8x-11=4x^{2}-4x+1
    -8x+4x=11+1
    -4x=12
    x=-12/4
    x=-3

    d) (x+3)(x-2) =(x-4)(x-5)+3x+15
    x^{2}-2x+3x-6=x^{2}-5x-4x+20+3x+15
    x^{2}+x-6-x^{2}+6x=35
    7x=41
    x=41/7

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